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" E are the complete elliptic integrals of the first and second kind respectively... "
Physical Review - Página 469
1912
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Bulletin of the Bureau of Standards, Volumen2

United States. Bureau of Standards - 1906 - 522 páginas
...radii of the two circles, d is the distance between their centers, and tJAa k=—.. . *---.^==i = s1n 7 /•"and E are the complete elliptic integrals of the first and second kind, respectively, to modulus k. Their values may be obtained from the tables of Legendre, or the values of Mt- \irJAa may...
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Bulletin of the Bureau of Standards, Volumen2

United States. National Bureau of Standards - 1906 - 540 páginas
...where and .• in the expression for V b+b' , . .. . , ., f=— — — c 1n the express1on for Vl F and E are the complete elliptic integrals of the first and second kinds respectively, to modulus £, where *«=-. and ^"(y) are the incomplete elliptic integrals...
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Bulletin of the Bureau of Standards, Volumen2

United States. Bureau of Standards - 1906 - 542 páginas
...where (34) and where and c= in the expression for V b+b' , c=- — — c' i in the expression for Vl F and E are the complete elliptic integrals of the first and second kinds respectively, to modulus £, where __ -« 'T and ^(y) are the incomplete elliptic integrals...
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Bulletin of the Bureau of Standards, Volumen8

United States. Bureau of Standards - 1913 - 840 páginas
...r? \n. — a.— 'ia cos* 7 + 8«, cos* 7! o. jg L 1 <J !« / ' -! *J 800" cos' 7 = — j — -j-4 and F and E are the complete elliptic integrals of the first and second kinds with modulus k = sin 7. When the coils have equal breadth £, = £,= £ and a^ = £',...
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Proceedings of the Cambridge Philosophical Society: Mathematical ..., Volumen23

Cambridge Philosophical Society - 1927 - 1078 páginas
...(5-5), *here A is an arbitrary constant and 2 .'o"1 cos2<f>d<j> Jy sin2 <f> (5-51) (5-52), K and E being the complete elliptic integrals of the first and second kind respectively to the modulus sin Jy. By considering the integral in equation (5-51) we can show that r/X or y' steadily increases...
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Scientific Papers of the Bureau of Standards, Volumen21

United States. National Bureau of Standards - 1927 - 934 páginas
...cases n=0 and n= 1 (44) shows that = ¿K(p) (45) 4¿¿(p) ¿ 1)K(¿) _¿E(p)} (46) where K(j4 and E(p) are the complete elliptic integrals of the first and second kind, respectively, whose modulus is p. Another useful relation derivable from (42) and (43) is 1 M =(¿+¿){ ¿ +(3—...
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Journal of Research of the National Bureau of Standards, Volumen16

United States. National Bureau of Standards - 1936 - 786 páginas
...values of Hx and H, are given by the equations: ~D\_(kl> +lz)E(kl') +(k*' +ft)E(k*)J (24) (25) where K and E are the complete elliptic integrals of the first and second kind, respectively, to the indicated moduli. (26) 16D(Dt) (27) Equation 23 was obtained as follows. Let H denote the magnetic...
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Science Abstracts: Physics. Section A, Volumen16

1913 - 772 páginas
...between their planes we have M = 4ir(Aa)1«[(2/* — A)F — (2/*)E], where A=2(Aa)W/[(A-|-a)»+d»]i/», and F and E are the complete elliptic integrals of the first and second kind respectively. If we write, <? + d? = r*, we get from the theory of elliptic functions M = 4jra[log (8a/r) . P —...
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Philosophical Magazine

1867 - 1174 páginas
...vortex-filament of indefinitely small section, putting adydc—m^ and the corresponding part of ^ = ^,ni, we have and F and E are the complete elliptic integrals of the first and second orders for the modulus K. If we put, for sake of brevity, U=?(FE)-*F, where, therefore, U is...
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Dynamics of Josephson Junctions and Circuits

Likharev - 1986 - 640 páginas
...0.8 >.O 1.2 (d) where x = \u\/Ug, z' = (1 - x 2)1/2, ug is the gap frequency (2.10) and K(x) and E(x) are the complete elliptic integrals of the first and second kind, respectively (see, eg, Reference 1.41). Real parts of the functions Ip q(U) are always even and the imaginary parts...
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